Determine the axis of symmetry for the function f(x)=-2(x+3)^2-5

x=-3

Step-by-step explanation:

f(x)=-2(x+3)^2-5

The equation is in the form

f(x) = a(x-h)^2 -k

where (h,k) is the vertex

The h value is also the axis of symmetry

f(x)=-2(x--3)^2-5

The vertex is (-3,-5)

so the axis of symmetry is x=-3

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3