Determine the axis of symmetry for the function f(x)=-2(x+3)^2-5

x=-3

Step-by-step explanation:

f(x)=-2(x+3)^2-5

The equation is in the form

f(x) = a(x-h)^2 -k

where (h,k) is the vertex

The h value is also the axis of symmetry

f(x)=-2(x--3)^2-5

The vertex is (-3,-5)

so the axis of symmetry is x=-3

5x+10 is the correct one

hope this

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead