The passing yards for the top 5 quarterbacks in the country are 3,832, 3,779, 3,655, 3,642, and 3,579. find the variance and standard deviation. round to the nearest hundredth.
(explain work)

Explanation:

In order to calculate the variance and standard deviation of a set of data, you first must calculate the mean.

Mean = average = μ = ∑ values / (number of data)

Hence, the mean of our data set is:

Now you can calcuate the variance using the formula.

For a data set (which is all your population and not a sample) the formula is:

That is:

The standard deviation, S.D., is the square root of the variance:

Variance = 8732.24 and standard deviation = 93.45

Step-by-step explanation:

We have to calculate the variance and standard deviation of the data set

3,832, 3,779, 3,655, 3,642, 3,579

First we calculate the mean of the data

Mean =

         =

         = 3697.4

Now we calculate the variance by subtracting the mean from value of data set and square it.

3832 - 3697.4 = 134.6² =  18,117.16

3779 - 3697.4 = 81.6² = 6,658.56

3655 - 3697.4 = -42.4² = 1,797.76

3642 - 3697.4 = -55.4 = 3069.16

3579 - 3697.4 = -118.4 = 14,018.56

Add up the squared result and take the mean

=  

=  

Variance = 8732.24

To calculate standard deviation, we take the square root of the variance =

Standard deviation = 93.44645526 ≈ 93.45

Variance = 8732.24 and standard deviation = 93.45

a) 0

step-by-step explanation:

i^413 x i^0 = 0 as any number multiplied by a zero is

happy to

pls mark as brainliest.

if your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:

max = c - (b2 / 4a).

the first step is to determine whether your equation gives a maximum or minimum.

-x2 + 4x - 2.     thats an example hope it