Which shows one way to determine the factors 4x^3+x^2-8x-2 by grouping

Step-by-step explanation:

Note that the first two terms have the factor 4x + 1 and that this is also a factor of the last two terms.  Thus, 4x^3+x^2-8x-2 = (4x + 1)(x^2 - 2).  This last result is further factorable:  (4x + 1)(x - √2)(x + √2).

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y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4