Which statements about this system of equations are true? check all that apply. - x + 6y = 16 8x - 6y = -2 the x-variable will be eliminated when adding the system of equations. the y-variable will be eliminated when adding the system of equations. the sum of the system of equations is - x + 6ythere is only one solution to the system of equations.

The true statements are:

The y-variable will be eliminated when adding the system of equations

There is only one solution to the system of equations is

Step-by-step explanation:

* Lets explain how to solve the problem

- We use the elimination method to solve the system of the

  linear equation

- The solution is one of three cases

# Exactly one solution ⇒ the 2 lines which represented the equations

  intersect each other at one point

# No solution ⇒ the 2 lines which represented the equations are

  parallel to each other

# Infinite solutions ⇒ the two lines are coincide

- In the system of the linear equations of the problem we have two

 linear equations  -x + 6y = 16 and 8x - 6y = -2

- To solve we must to eliminate one of the two variables

∵ The y's in the two equations have the same coefficients and

   different signs

∴ We add the equations to eliminate y

∴ (-x + 8x) + (6y - 6y) = 16 + -2

∴ 7x = 14 ⇒ divide both sides by 7

∴ x = 2

- Substitute the x in any one of the two equations by 2

∴ -2 + 6y = 16 ⇒ add 2 to both sides

∴ 6y = 18 ⇒ divide both sides by 6

∴ y = 3

∴ The solution of the system of the equations is (2 , 3) ⇒ only one

   solution

- Lets check the statements to find the true statements

# The x-variable will be eliminated when adding the system of

   equations is not true

# The y-variable will be eliminated when adding the system of

   equations is true

# The sum of the system of equations is - x + 6y is not true

# There is only one solution to the system of equations is true

sss (side, side, side)

sas (side, angle, side)

asa (angle, side, angle)

aas (angle, angle, side)

hl (hypotenuse, leg)

146%

step-by-step explanation: