Evaluate f(x) =3 |x-2| + 1 for f(-2) and f(1)

Step-by-step explanation:

f(-2) = 3*abs(x - 2) + 1

f(-2) = 3*abs(-2-2) + 1

f(-2) = 3* abs(-4) + 1

f(-2) = 3 * 4 + 1

f(-2) = 13

f(1) = 3*abs(1 - 2) + 1

f(1) = 3*abs(-1) + 1

f(1) = 3*1 + 1

f(1) = 4

-6 is the correct option from the above given options