Find the vertex of the parabol whose equatio is y =3x^2+6x+1

(-1,-2)

Step-by-step explanation:

y=ax^2+bx+c

Find -b/(2a) and you will have found the x-coordinate of the vertex of this parabola.

You can find the y-coordinate that corresponds to it by plugging in your into the original equation.

-b/(2a)=-6/(2*3)=-6/6=-1

Now replace x with -1

3(-1)^2+6(-1)+1

3-6+1

-3+1

-2

So the vertex is (-1,-2)

don't know sorry bru

step-by-step explanation:

cosine

step-by-step explanation: