The mean and the standard deviation of a sampled population are, respectively, 113.9 and 32.1. find the mean and standard deviation of the sampling distribution of the sample mean for samples of size n=64. round your answers to one decimal place.

The mean of the sample is 113.9, and the standard deviation of the sample is 4.0

The given parameters are:

--- the population mean

--- the population standard deviation

--- the sample size

The sample mean is calculated as:

So, we have:

The sample standard deviation is calculated as:

This gives

Hence, the mean of the sample is 113.9, and the standard deviation of the sample is 4.0

Read more about mean and standard deviation at:

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The mean and standard deviation of the sampling distribution of the sample mean for samples of size n=64 is

respectively.

Step-by-step explanation:

Given : The mean of sampled population :

The standard deviation of sampled population :

We know that the mean and standard deviation of the sampling distribution of the sample mean for samples of size n is given by :_

Now, the mean and standard deviation of the sampling distribution of the sample mean for samples of size n=64 will be :-

i just took the test, the correct answer is .. 31.5 in.

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right