Curve fitting the following application of linear algebra to curve fitting is explained in greater detail in section $3.7 of your text (page 218). (a) determine the equation of a line passing through the points (-1,-2) and (3,2) in the following way. assume the line has equational form and put both data points into equation (1) to get two equations in the two unknowns co and cy. write this system of equations as a matrix equation of the form: ax - b now use any linear algebra technique you like (row reduction on the augmented matrix, cramer's rule, or compute a-b) to solve for the unknowns x (co, c).

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3

2x^2+5x+17

your welcome. : )

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)