Efgh is a rhombus,
given eg = 16 and fh = 12, what is the length of one side of
the rhombus?
6 units
8 units
10 units
14 units

C. 10 units

Step-by-step explanation:

The half diagonals of a rhombus are the legs of a right triangle with the hypotenuse being the side of the rhombus.

EG and FH are the diagonals of the rhombus. The half-diagonals measure 8 and 6.

We can use the Pythagorean theorem to find the hypotenuse length with is the length of the side of the rhombus.

a^2 + b^2 = c^2

8^2 + 6^2 = c^2

64 + 36 = c^2

100 = c^2

c^2 = 100

c = 10

10 units

10    took the test     hope this helps!    :)

Step-by-step explanation:

EFGH is a rhombus.

Rhombus E F G H is shown. Diagonals are drawn from point E to point G and from point F to point H. All sides are congruent.

Given EG = 16 and FH = 12, what is the length of one side of the rhombus?

6 units

8 units

10 units

14 units

the least common denominatore of 7 and 2 is 9

step-by-step explanation:

7+2=9

i would you but i don't under stand the qustion

step-by-step explanation: