Lauren in making 15 liters of mimosas for a brunch banquet. orange juice costs her $1.50 per liter and champagne costs her $12 per liter. how many liters of orange juice and how many liters of champagne should she use for the mimosas to cost lauren $5 per liter?

Step-by-step explanation:

Let c represent the number of liters of champagne Lauren uses. Then (15-c) will be the number of liters of orange juice. The total cost of the mix will be ...

  12c +1.50(15-c) = 5.00(15)

  10.5c = 52.50 . . . . . subtract 22.50, simplify

  52.50/10.5 = c = 5 . . . . divide by the coefficient of c

Then the amount of orange juice is ...

  15 -c = 15 -5 = 10 . . . . liters

Lauren should use 5 liters of champagne and 10 liters of orange juice.

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2