![= [3 (-2)^3 (5)^{-2}]^2\\We\ have\ to\ make\ the\ powers\ positive\\= [{\frac{3(-2)^3}{5^{2}} }]^2\\= \frac{[{3(-2)^3}]^2}{(5^2)^2} \\Applying\ outer\ power\\= \frac{3^2(-2)^6}{5^4} \\](/tpl/images/0024/4069/d8228.png)
Which shows how to find the value of this expression when x=-2 and y = 5?
(3x3y=272
31-...
Mathematics, 27.06.2019 19:20 macy2571
Which shows how to find the value of this expression when x=-2 and y = 5?
(3x3y=272
31-216
(-2)4
21954
Answers: 1
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