You are with some repairs at home. you drop a hammer and it hits the
floor at a speed of 8 feet per second. if the acceleration due to gravity (g) is
32 feet/second, how far above the ground (h) was the hammer when you
dropped it? use the formula:
v = 2gh

1 foot.

Step-by-step explanation

That is not the correct formula.  Correct is  V^2 = 2gh  where h = the height

so the equation is:

8^2 = 2*32* h

h = 64/ 64 = 1 foot.

Step-by-step explanation:

In order to be able to solve this problem you just have to clear the formula for height:

V=2gh

So the height from which the hammer is dropped is 1/8 feet.

3x + 4y -25 =0 represents the amount of change sianna should recieve

i need more details sorry

step-by-step explanation: