Find the solution of ivp for the differential equation (x+2)^2e^y when y(1) =0 y'= dy/dx=(x+2)^2.e^y; y(1)=0

The solution is

Step-by-step explanation:

We need to find the solution of IVP for differential equation when

Integrate both the sides with respect to dx

Since, IVP is y(1)=0

put x=1 and y=0 in above equation

add both the sides by

so,

Multiply both the sides by '-1'

Take natural logarithm both the sides,

Multiply both the sides by '-1'

Therefore, the solution is

hi there!

the answer to this question is d: 35

step-by-step explanation:

5 to the power of 2 is 25

2 multiplied by 5 is 10

then you add the 2 numbers and you get 35