An arena is hosting a rock concert. it has "silver" and "gold" seating sections. the event organizers are selling the first 100 gold tickets at the price of a
silver ticket. the price of a silver ticket is $7 more than 1/2 the price of a gold ticket. the price of a silver ticket is $14 less than 6/5 the price of a gold ticket.
how much will one of the first 100 buyers save on the price of a gold ticket?

s = the price of a silver ticket

g = the price of a gold ticket

s = 7 + (1/2)*g           (first relation)

s = (6/5)*g - 14        (second relation)

but (first relation) = (second relation) so we get

7 + (1/2)*g = (6/5)*g - 14

(6/5)*g - (1/2)*g = 7 + 14

(7/10)*g = 21

g = 30

from (first relation) we get s = 7 + (1/2)*30 = 22.

how much would someone save? the answer is g - s = 8.

Step-by-step explanation:

good luck on your studies! : )

david edward.

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.