Which graph correctly solves the system of equations below? y = − x2 + 1 y = x2 − 4
a) quadratic graph opening up and quadratic graph opening down. they do not intersect.
b) quadratic graph opening up and quadratic graph facing down. they intersect at negative 2, negative 3 and 2, negative 3.
c) two intercepting parabolas are shown, one facing downward and one facing upward. the downward facing parabola has a maximum at (0,1) and intercepts the x axis at 1 and negative 1. the upward facing parabola has a minimum at (0,-4) and intercepts the x axis at 2 and negative 2
d) two quadratic graphs opening up. they intersect at 0, negative 4.

  C)  Two intercepting parabolas are shown, one facing downward and one facing upward. The downward facing parabola has a maximum at (0,1) and intercepts the x axis at 1 and negative 1. The upward facing parabola has a minimum at (0,-4) and intercepts the x axis at 2 and negative 2

Step-by-step explanation:

As shown in the attached, the graph of y = -x² +1 has its vertex at (0, 1) and opens downward. It crosses the x-axis at ±1. The graph of y = x² -4 has its vertex at (0, -4), opens upward, and crosses the x-axis at ±2. The description of this graph matches choice C.

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier