Astudent draws two parabolas on graph paper. both parabolas cross the x-axis at (–4, 0) and (6, 0). the y-intercept of the first parabola is (0, –12). the y-intercept of the second parabola is (0, –24). what is the positive difference between the a values for the two functions that describe the parabolas? write your answer as a decimal rounded to the nearest tenth

Lets say that y1 is the parabola with y intercept of (0,-12)

y1 = A(x+4)(x+6)

-12 = A(+4)(+6)

A = -0.5

y1 = -0.5(x+4)(x+6)

Step-by-step explanation:

The parabolas can be described

y = A.(x-x1)(x-x2)

where x1 and x2 are the crossing points in the x-axis

x1 = -4

x2 = 6

Lets say that y1 is the parabola with y intercept of (0,-12)

y1 = A(x+4)(x+6)

-12 = A(+4)(+6)

A = -0.5

y1 = -0.5(x+4)(x+6)

Lets say that y2 is the parabola with y intercept of (0,-24)

y2 = B(x+4)(x+6)

-24 = B(+4)(+6)

B = -1

y2 = -(x+4)(x+6)

The positive difference is 0.5

-0.5

Step-by-step explanation: