Asensitive measuring device is calibrated so that errors in the measurements it provides are normally distributed with mean 0 and variance 2.00. find the probability that a given error will be between -3 and 3.

0.9660

Step-by-step explanation:

Given: Mean :

Variance :

⇒ Standard deviation :

The formula to calculate z is given by :-

For x= -3

The P Value =

For x= 3

The P Value =

Hence, the probability that a given error will be between -3 and 3=0.9660

answer: plz put a pic in so i can answer it

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)