Mathematics, 22.06.2019 19:20 thelonewolf5020
Consider the curve of the form y(t) = ksin(bt2) . (a) given that the first critical point of y(t) for positive t occurs at t = 1 tells us that y '(0) = 1 y(0) = 1 y '(1) = 0 y(1) = 0 given that the derivative value of y(t) is 3 when t = 2 tells us that y '(3) = 2 y '(0) = 2 y '(2) = 0 y '(2) = 3 (b) find dy dt = kcos(bt2)·b2t (c) find the exact values for k and b that satisfy the conditions in part (a). note: choose the smallest positive value of b that works.
Answers: 2
Mathematics, 21.06.2019 22:30
Which statements about the system are true? check all that apply. y =1/3 x – 4 3y – x = –7 the system has one solution. the system consists of parallel lines. both lines have the same slope. both lines have the same y–intercept. the equations represent the same line. the lines intersect.
Answers: 2
Mathematics, 22.06.2019 00:00
What is the effect on the graph of the function f(x) = x2 when f(x) is changed to f(x) − 4?
Answers: 1
Consider the curve of the form y(t) = ksin(bt2) . (a) given that the first critical point of y(t) fo...
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