Where are the astmptotes for the following function located f(x)=7/x^2-2x-24

Hence, the asymptotes of f(x) located at x=6 and x=-4.

Step-by-step explanation:

Since we have given that

f(x)= \frac{7}{x^2-2x-24}

We need to find the asymptotes for the above function:

Asymptotes occur when denominator becomes zero.

x^2-2x-24=0x^2-6x+4x-24=0x(x-6)+4(x-6)=0(x-6)(x+4)=0x=6,-4

table a is wierd

step-by-step explanation:

6*f