How can (1/2)x-5=(1/3)x+6 be set up as a system of equations? answers: a) 2y+x=-10 3y+x=18 b) 2y+2x=-10 3y+3x=18 c) 2y-x=-10 3y-x=18 d) 2y-2x=-10 3y-3x=18

 C)

Step-by-step explanation:

Set each side of the equation equal to y, then rearrange to standard form.

  (1/2)x -5 = y . . . left side of the equal sign

  x -10 = 2y . . . . multiply by 2

  -10 = 2y -x . . . . subtract x

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  (1/3)x +6 = y . . . right side of the equal sign

  x +18 = 3y . . . . . multiply by 3

  18 = 3y -x . . . . . subtract x

The corresponding system of equations is ...

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: