An engineer on the ground is looking at the top of a building. the angle of elevation to the top of the building is 46°. the engineer knows the building is 250 ft tall. what is the distance from the engineer to the base of the building to the nearest whole foot?

=241 ft

Step-by-step explanation:

The building is opposite the angle of elevation. Thus using trigonometric ratios it is easier to use Tangent of the elevation angle to find the distance to the foot of the building (adjacent).

Tan ∅ = opposite/ adjacent

Tan ∅= height of the building/ distance between the engineer and the building

distance= height/tan ∅

=250/tan 46°

=241 ft

          =

241 feet.

Step-by-step explanation:

Observe the figure attached, where "x" is the distance from the engineer to the base of the building to the nearest whole foot.

We need to remember this identity:

In this case we know that:

Therefore, the next step is to substitute these values into  :

And the final step is to solve for "x":

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range: