Can somebody me solve this? "the measures of two complementary angles are 6y + 3 and 4y - 13. find the measures of the angles."

The measures of two complementary angles are 63° ,  27°

Step-by-step explanation:

The measures of two complementary angles are 6y + 3 and 4y - 13.

Sum of complementary angles = 90°

6y + 3  + 4y - 13 =  90°

10y - 10 =  90°

10y = 90 + 10 = 100

10 y = 100

y    = 100/10 = 10

One angle = 6y + 3 = 6 * 10 + 3 = 60 + 3 = 63

other angle = 4y - 13 = 4 * 10 - 13 = 40 - 13 = 27

The angles are 63° ,  27°

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!