Consider the integral: b integrate 0 squreroot 64 - y^2 integtrate -squreroot 64 - y^2 b integrate squreroot x^2 + y^2 1 dz dx dy. describe w use the standard view of the x, y, and z axes. right half of a cone with a flat top. full cone with a flat top. front half of a cone with a rounded top. front half of a cone with a flat top. right half of a cone with a rounded top. set up the integral in spherical coordinates. 1 p^2 sin (phi) dp dphi dtheta why can we avoid integration and use only geometry to evaluate the integral in part (b)? the integral represents the volume of a solid and we know the formula for the volume. the integration is very simple and we can evaluate the integral without work. the integrand is 1 and we can always avoid integration and use geometry when the integrand is 1. using geom, entry, what is the value of the integral?