Identify the form of the equation and two characteristics(example: slope, y--intercept, or point) of the function's graph. 1. y = –7x + 2 2. y + 2 = 2/3(x – 5)

1) graphical linear equation form (slope = -7, y-intercept = 2)

2) Standard linear form (slope = 2/3, y-intercept = -4/3)

Step-by-step explanation:

1) A graphical equation is always in the form of y = mx + c where y is the subject.

slope is the value before x which is -7

Y-intercept is where a line meets y axis so the value of x is 0. Y-intercept is 2.

y = -7x + 2

y= -7 (0) + 2 = 2

2) A standard form is where y is not the subject.

Step 1: Convert it into graphical equation form y = mx + c to identify the slope and y-intercept.

y + 2 = 2/3(x – 5)

y + 2 = 2/3x - 10/3

y = 2/3x - 10/3 -2

y= 2/3x - 4/3

slope is the value before x which is 2/3

Y-intercept is where a line meets y axis so the value of x is 0. Y-intercept is -4/3.

y= 2/3x - 4/3

y = 2/3 (0) - 4/3

y = -4/3

!!

answer: idk

step-by-step explanation:

50-38=12

step-by-step explanation: