What is the equation of the line perpendicular to y=2/3x+1 that passes through the point (12, –6)? a. 3x + 2y = 24 b. 3x + 2y = 6 c. 2x – 3y = 42 d. 2x – 3y = –48

Step-by-step explanation:

Start with y=(2/3)x+1 . The slope of any line perpendicular to this is the negative reciprocal of 2/3:  -3/2.

Then we have y = mx + b, which, using the given data (12, -6), becomes

-6 = (-3/2)(12) + b, or

-6 = -18 + b, so b = 12 and y = (3/2)x + 12.

We must put this into standard form.  Mult. all three terms by 2:

2y = 3x + 24      

what "following statement"?

step-by-step explanation:

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: