The length of one of the legs in a right triangle is 3 inches . if the hypotenuse is 10 inches long what the length of the other leg

9.5 inches

Step-by-step explanation:

We are given that in a right angled triangle, one leg is 3 inches long while the hypotenuse is 10 inches long. We are to find the length of the other leg.

For this, we will use the Pythagoras Theorem.

Assuming x to be the length of the other leg.

x = 9.5

9.53 inches

Step-by-step explanation:

In a right  angles triangle, the sum of the squares of the two legs (a and b) equals the square of the the hypotenuse.

a²+b²=c²

Substituting for the values provided in the question we get the following:

3²+b²=10²

b²=10²-3²

b²=91

b=9.53 inches.

this may not be at all, but i use the same website you're using for school, and if i'm stuck doing one of these i try to look for it on the section.

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240