Which of the following shows the true solution to the logarithmic equation below? log(x)+ log(x+5) = log(6x +12) © x=-3 x=4 x=-3 and x = 4 x=-3 and x=-4

x = 4.

Step-by-step explanation:

log(x) + log(x+5) = log(6x +12)

log x(x +5) = log(6x + 12)

Therefore x(x + 5)= 6x +12

x^2 + 5x - 6x - 12 = 0

x^2 - x - 12 = 0

(x - 4)(x + 3) = 0

x = -3, 4.

logs of negative values do not exists so the anser is x = 4.

©

X=4 or B on Edge 2020

Step-by-step explanation:

srry idk

step-by-step explanation: