Aproton moves at 5.20 105 m/s in the horizontal direction. it enters a uniform vertical electric field with a magnitude of 8.40 103 n/c. ignore any gravitational effects. (a) find the time interval required for the proton to travel 4.50 cm horizontally.

  86.5 ns

Step-by-step explanation:

The speed in the original direction (horizontally) is unchanged by the vertical force the field exerts. The travel time is ...

  time = distance/speed = (4.5×10^-2 m)/(5.20×10^5 m/s) = 8.65×10^-8 s

An engineer would express this time using the SI prefix nano- for 10^-9. The time is 86.5 ns.

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

answer: you will have more water.