Now consider two springs a and b that are attached to a wall. spring a has a spring constant that is four times that of the spring constant of spring b. if the same amount of energy is required to stretch both springs, what can be said about the distance each spring is stretched

Step-by-step explanation:

The energy required to stretch a spring a distance x is:

E = ½ kx²

where k is the stiffness constant.

If spring B has a constant k and is stretched a distance of b:

E = ½ k b²

If spring A has a constant of 4k and is stretched a distance of a:

E = ½ (4k) a²

E = 2 k a²

If the energies are the same:

½ k b² = 2 k a²

b² = 4 a²

b = 2a

So spring B is stretched twice as far as spring A.

30 miles

step-by-step explanation:

we know that 60 seconds equals 1 minute and 60 minutes 1 hour

44 ft       60 sec     60 min     158400   ft

  *   *   =

1 sec       1 min       1 hour         hour

we know that there are 5280 ft per mile

158400   ft       1 mile         30 miles

  *   =

1   hour               5280 ft     1 hour

so in 1 hour   it can travel 30 miles