Solving quadratic equations using squaresx^2 +6x-7=0

Step-by-step explanation:

Do you mean by completing the square?

x² + 6x - 7 = 0

x² + 6x = 7

Take half of 6, square it, and add to both sides.  (6/2)² = 9.

x² + 6x + 9 = 7 + 9

(x + 3)² = 16

x + 3 = ±4

x = -3 ± 4

x = -7, 1

So the roots are x=-7 and x=1.

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,