Which point could be on the line that is parallel to line kl and passes through point m? (-10,0) (-6,2) (0,-6) (8,-10)

(8,-10)

Step-by-step explanation:

step 1

Find the slope of line KL

K(-6,8),L(6,0)

m=(0-8)/(6+6)

m=-8/12=-2/3

step 2

Find the slope of the line that is parallel to KL

we know that

If two lines are parallel , then their slopes are the same

therefore

The slope of the parallel line to KL is m=-2/3

step 3

Find the equation of the line parallel to KL that pass through the point M

M(-4,-2)

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y+2=-(2/3)(x+4)

step 4

Verify the points

we know that

If the point lie on the line, then the point must satisfy the equation of the line

case a) (-10,0)

substitute the value of x and the value of y in the equation and then compare the result

-10+2=-(2/3)(0+4)

-8=-8/3 > is not true

therefore

The point is not on the line

case b) (-6,2)

substitute the value of x and the value of y in the equation and then compare the result

2+2=-(2/3)(-6+4)

4=4/3 > is not true

therefore

The point is not on the line

case c) (0,-6)

substitute the value of x and the value of y in the equation and then compare the result

-6+2=-(2/3)(0+4)

-4=-8/3 > is not true

therefore

The point is not on the line

case d) (8,-10)

substitute the value of x and the value of y in the equation and then compare the result

-10+2=-(2/3)(8+4)

-8=-8 > is true

therefore

The point is on the line

step-by-step explanation: yes

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents