Write a function to represent the set of ordered pairs. {(2, -8), (3, -18), (4, -32), (5, -50)}

y = -2x²

Step-by-step explanation:

The set of ordered pairs is:

(x₁, y₁) = (2, -8)

(x₂, y₂) = (3, -18)

(x₃, y₃) = (4, -32)

(x₄, y₄) = (5, -50)

First let's check if this is linear.  For even increments of x, Δy is:

Δy₂₁ = y₂ − y₁ = -18 − -8 = -10

Δy₃₂ = y₃ − y₂ = -32 − -18 = -14

Δy₄₃ = y₄ − y₃ = -50 − -32 = -18

Δy isn't constant, so this isn't linear.  However, the difference of the differences is constant:

Δy₃₂ − Δy₂₁ = -14 − -10 = -4

Δy₄₃ − Δy₃₂ = -18 − -14 = -4

So this is a quadratic.

y = ax² + bx + c

To find the coefficients of a, b, and c, we can either plug in three points from the set and solve the system of equations:

-8 = a(2)² + b(2) + c

-18 = a(3)² + b(3) + c

-32 = a(4)² + b(4) + c

Or, if it's simple, we can use a little trial and error.

-8 = -2 (2)²

-18 = -2 (3)²

-32 = -2 (4)²

So the function is:

y = -2x²

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

f(x) = y

f(-3) = -5

step-by-step explanation: