What are the domain and range of the function f(x)=-square root x+3-2?

For this case we have the following function:

By definition, the domain is given by all the values for which the function is defined.

The given function is no longer defined if the argument of the root is negative. So:

Thus, the domain of the function is given by all the values of x greater than or equal to -3.

Domain: [-3, ∞)

Substituting the values of the domain, we find the range.

The function evaluated in ∞ gives -∞. So the range is given by:

(-∞, 2]

Domain:  [-3, ∞)

Range: (-∞, 2]

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb