(4 marks) 5. solve the following equations: a) x+5 = 7 b) 2x - 8 = 20 c) 4x - 6x = 200 d) x+1= 5 3

a) x + 5 = 7

x + 5 - 5 = 7 - 5 (Subtract 5 from both sides)

x = 2

b) 2x - 8 = 20

2x - 8 + 8 = 20 + 8 (Add 8 to each side)

2x = 28

2x/2 = 28/2 (Divide each side by 2)

x = 14

c) 4x - 6x = 200

-2x = 200

-2x/-2 = 200/-2 (Divide each side by -2)

x = -100 (Note that a negative number divided by a negative number is positive, whereas a positive number divided by a negative number is negative)

d) x + 1 = 5

x + 1 - 1 = 5 - 1 (Subtract 1 from each side)

x = 4

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

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