Extend the terminal arm to include the point q(4,8). determine sinfata for the angle in standard position whose terminal arm passes through point q

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

the question you are asking is very confusing and there is no answer to the question you are persuing. quotients are found in division and your asking us to multiply so therefore there is no answer

brainliest plzz

to prove δxyz ≅ δmno using sss, you need to show the following:

  side 1             side 2               side 3

xy ≅ mn         yz ≅ no           xz ≅ mo

to prove δxyz ≅ δmno using sas knowing side xz and angle o, you need to show the following:

side 1             connecting angle           side 2

xz ≅ mo             ∠z ≅ ∠o                   yz ≅ no