Ajumbo crayon is composed of a cylinder with a conical tip. the cylinder is 12 cm tall with a radius of 1.5 cm, and the cone has a slant height of 2 cm and a radius of 1 cm. the lateral area of the cone is π cm2. to wrap paper around the entire lateral surface of the cylinder, π cm2 of paper is needed. the surface area, including the bottom base of the crayon, is π cm2.

Part 1) The  lateral area of the cone is

Part 2) The lateral surface area of the cylinder is

Part 3) The surface area of the crayon is

Step-by-step explanation:

Part 1) Find the  lateral area of the cone  

The lateral area of the cone is equal to

we have

substitute

Part 2) Find the lateral surface area of the cylinder

The lateral area of the cylinder is equal to

we have

substitute

Part 3) Find the surface area of the crayon

The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon

Find the area of the bottom base of the crayon

where

r2 is the radius of the cylinder

r1 is the radius of the cone

substitute

Find the area of the top base of the cylinder

Find the surface area

srry idk

step-by-step explanation: