Find three consecutive positive even integers such that the product of the second and third integers is 20 more than 10 times the first integer.

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier

127

whether it's diameter, or radius, i believe if i remember correctly from school, every amount has to always add up to 180. so if you take 53, and starting adding, long story short, taking 127 and adding it to 53, gives you 180.

25/6 hope it : )

step-by-step explanation:

i think the answer is a.( -3, -1 )