The length of a rectangle is 8 mm longer than its width. its perimeter is more than 32 mm. let w equal the width of the rectangle. a. write an expression for the length in terms of the width. b. use expressions for the length and width to write an inequality for the perimeter, on the basis of the given information. c. solve the inequality, clearly indicating the width of the rectangle.

Part A

w = width

L = length

L = w+8 since the length is 8 mm longer than the width

Part B

P = perimeter of rectangle

P = 2*(L+W) = 2L + 2W

We want the perimeter to be more than 32 mm, so we want P to be greater than 32

This means we write P > 32

Replace P with either 2(L+W) or 2L+2W. I'll pick 2L+2W

So we go from

P > 32

to

2L+2W > 32

After this, replace L with W+8 (refer to part A above)

We now have

2(W+8) + 2W > 32

Part C

Let's solve the inequality found in part B to get...

2(w+8) + 2w > 32

2w + 16 + 2w > 32

4w + 16 > 32

4w + 16-16 > 32-16 subtracting 16 from both sides

4w > 16

4w/4 > 16/4 dividing both sides by 4

w > 4

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.