Let r be the region bounded by y=x and y=x^2.find the area of r. find the volume of the solid that results when r is revolved about the x-axis(using the shell method).

2pi/15

Step-by-step explanation:

The intersection of y=x and y=x^2 is (0,0) and (1,1)

Washer method

Prefered this method for this one since slices are perpendicular to axis of rotation

Integrate(Big circle - Small Circle)dx

Integrate(pi*(x)^2-pi*(x^2)^2)dx on x=0..1

Integrate(pi*x^2-pi*x^4)dx on x=0..1 is 2pi/15

Shells method

So I have to solve for x since I will be integrating with respect to y

The height of the the shell will be sqrt(y)-y

The radius will be y since that is the distance between axis of rotation in a point within the shell

Integrate(2*pi*r*h ) dy

Integrate(2*pi*(sqrt(y)-y)*y) dy on y=0..1 is 2pi/15

first option

a function is a relation in which an input is paired with exactly one output.

so, let's find the right answer.

in our first option, our inputs are january, february, and march. the outputs are 30, 28, and 25. each input has it's own output. this is correct!

our second option we know is incorrect, because ms. valverade has two outputs, dogs and cats. this is not a function.

our third option is incorrect as well. the yellow square has two ouputs, the square and the triangle.

lastly, in our fourth option, we see the number 7 two times with a different output. therefore, this is not a function.

remember: each input must be paired with only one output!