Irequire some assistance with this graphing question, . "use the parabola tool to graph the quadratic function f(x)=−(x+3)^2+5 graph the parabola by first plotting its vertex and then plotting a second point on the parabola." the graph's max on both the x and y axis is 10, and goes no further. any would be appreciated, but feel free to take your time.

vertex (-3,5) and another pt (-2,4)

Step-by-step explanation:

It is in vertex form so the vertex is (-3,5)...

Now just plug in a value for x say like -2...

f(-2)=-(-2+3)^2+5

f(-2)=-(1)^2+5

f(-2)=-1+5

f(-2)=4

So another point is (-2,4)

i belive those are the ones that are under 90 degreese.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it