The vertex of a quadratic function is located at (1,4) and the y-intercept of the function is (0,1). what is the value of a if the function is written in the form y=a(x-h)^2+k

  a = -3

Step-by-step explanation:

Put the y-intercept values into the equation and solve for a.

  1 = a(0 -1)^2 +4 . . . . with (h, k) filled in, this is y=a(x-1)^2+4

  -3 = a . . . . . . . . . subtract 4, simplify

The value of a is -3.

step-by-step explanation: where's the phrase?

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