Circle 1 is centered at (5, 8) and has a radius of 8 centimeters. circle 2 is centered at (1, −2) and has a radius of 4 centimeters. what transformations can be applied to circle 1 to prove that the circles are similar? enter your answers in the boxes.

The answer in the procedure

Step-by-step explanation:

we know that

Figures can be proven similar if one, or more, similarity transformations (reflections, translations, rotations, dilation's) can be found that map one figure onto another.  

In this problem to prove circle 1 and circle 2 are similar, a translation and a scale factor (from a dilation) will be found to map one circle onto another.

we have that

Circle 1 is centered at (5,8) and has a radius of 8 centimeters

Circle 2 is centered at (1,-2) and has a radius of 4 centimeters

step 1

Move the center of the circle 1 onto the center of the circle 2

the transformation has the following rule

(x,y)> (x-4,y-10)

so

(5,8)> (5-4,8-10)> (1,-2)

center circle 1 is now equal to center circle 2  

The circles are now concentric (they have the same center)

step 2

A dilation is needed to decrease the size of circle 1 to coincide with circle 2

scale factor=radius circle 2/radius circle 1> 4/8> 0.5

radius circle 1 will be=8*scale factor> 8*0.5> 4 cm

radius circle 1 is now equal to radius circle 2  

therefore

A translation, followed by a dilation will map one circle onto the other, thus proving that the circles are similar

answer: 5100 just subtract

step-by-step explanation:

step-by-step explanation:

the ratio of red paint to blue paint is always 9/7. that means that, whatever x's value, (4x+12)/(4x-4) has that same ratio. so, set up an equation and cross-multiply to solve for x:

9/7 = (4x+12)/(4x-4)

9(4x-4) = 7(4x+12)

36x - 36 = 28x + 84

8x - 36 = 84

8x = 120

x = 15