Find the slope-intercept equation of the tangent line to the graph of f(x)=x^2 at (-3,9).

  y = -6x -9

Step-by-step explanation:

The derivative is ...

  f'(x) = 2x

so the slope at x=-3 is ...

  f'(-3) = 2(-3) = -6

Then the point-slope form of the tangent line can be written ...

  y = m(x -h) +k . . . . . . for line with slope m through point (h, k)

  y = -6(x -(-3))+9 = -6x -18 +9 . . . . . filling in your values, eliminating parens

So, the slope-intercept equation of the tangent line is ...

  y = -6x -9

At a constant it will take one hour to travel 32 mi.at that speed it will take 1/2 hr to travel the remaining 16 mi.it will take 1+1/2 hr to travel the 48mi @ 32mph.so 1 hr = 60 min& 1/2 hr = 30 min1+1/2 hr = 90 min.there are 60s in each 90 × 60 = 3600 seconds.the real question seriously is he why are they driving so slow? ! lol.

The answer is: y would equal 3 because if you simplify the equation then it would be y= 3x+9 and if you divide 3x and 9 by 3 it would equal 3. y= 3