14. factor the polynomial by grouping, if possible. 3v2w – 21vw – 3v2 + 21v a. 3vw(v – 7) – 3(w – 1) b. 3v(v – 7)(w – 1) c. it can't be factored. d. 3v(v – 7)(v + 1)

3 v (v - 7) (w - 1) thus the answer is B:

Step-by-step explanation:

Factor the following:

3 v^2 w - 21 v w - 3 v^2 + 21 v

Factor 3 v out of 3 v^2 w - 21 v w - 3 v^2 + 21 v:

3 v (v w - 7 w - v + 7)

Factor terms by grouping. v w - 7 w - v + 7 = (v w - 7 w) + (7 - v) = w (v - 7) - (v - 7):

3 v w (v - 7) - (v - 7)

Factor v - 7 from w (v - 7) - (v - 7):

 3 v (v - 7) (w - 1)

angles 1 and 3 are vertical angles, meaning that they are equal to each other. to solve this you may set angle 1 and 3 equal to each other and just solve for x like

110 = 2x + 10

100 = 2x

50 = x

check:

110 = 2* 50 + 10

110 = 100 + 10

110 = 110

hope this !

~just a girl in love with shawn mendes