Ahyperbola centered at the origin has a vertex at (-6, 0) and a focus at (10,0). vertices: (-a,,0) foci: (-0,,0) asymptotes: y= x vertices: (0,-,a) foci: (0,-,c) asymptotes: y=x directrices: x=rated standard equation. directrices: yabang standard equation. standard equation: - standard equation: so 'x10 -1 which are the equations of the directrices?

whose power in the senate is equal to the power of the speaker of the house?

step-by-step explanation:

the answer for the question that you are asking is 4

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen