Calcule o valor de x nos casos abaixo, sabendo que y = 3. a) 7x + 2y + x + 2y = 0 b) 2x + 3y - x + 3x = 5 c) 1/3x + 1/5y = 0 d) 1/2x + 1/3x + 1/4y = 2 e) 0,25x - 0,30x - 0,35x + 1,2y = 2 f) 0,25x - 0,3y - 0,35y + 1,20y = 0 alguém consegue me ajudar com esses exercícios por favor?

answer is 12345678900987654321234567890987654321

step-by-step explanation:

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl