Agame called "small poker" is played with a standard deck of 52 playing cards (no jokers). in "small poker," each player is dealt four cards (called a "hand"). (a) how many four-card hands are possible?(b) how many four-card hands consisting of four hearts are possible?(c) how many four-card hands consisting of four aces are possible? . (d) how many four-card hands consisting of two pairs are possible? hint: two pairs cannot create a "four of a kind" combination

a. From 52 total cards, you're drawing 4:

b. There are 13 hearts in the deck, and you want all 4 to be drawn from that pool. From the remaining 39, you are drawing nothing:

c. Similar to (b), but there are only 4 aces in the deck, and you don't care about the remaining 48 cards:

d. There are 13 ranks (ace, 2, 3, ..., 10, jack, queen, king) from which you want to draw 2. For each given rank, there are 4 possible suits, and a two of a kind consists of drawing 2 cards of the same rank, regardless of suit. Once you have two pairs, you ignore the remaining.

That is, there are ways of getting two pairs if the two ranks are fixed. Then you multiply this by , the number of ways you can get two different ranks.

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step-by-step explanation:

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation: