Y= x ^ ( 2) - 6x + 2 rewrite in vertex form and state whether its maximum or minimum and give its coordinates

see explanation

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h,k) are the coordinates of the vertex and a is a multiplier

To obtain this form use the method of completing the square

add/subtract ( half the coefficient of the x- term)² to x² - 6x

y = x² + 2(- 3)x + 9 - 9 + 2 = (x - 3)² - 7 ← in vertex form

with vertex = (3, - 7)

To determine whether maximum or minimum consider the value of a

• If a > 0 then minimum

• If a < 0 then maximum

here a = 1 > 0 ⇒ minimum

Hence (3, - 7) is a minimum

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

take it another