Two angles of a triangle have the same measure and the third one is 12 degrees greater than the measure of each of the other two. find the measure of the largest angle in the triangle. nah

68

Step-by-step explanation:

Let x be the measure of one of the angles of the triangle

Two of the angles have the same measure, so another angle is x

The third is 12 degrees more, x+12

The sum of the three angles of a triangle is 180

x+x+x+12 = 180

Combine like terms

3x+12 = 180

Subtract 12 from each side

3x+12-12 = 180-12

3x = 168

Divide by 3

3x/3 = 168/3

x = 56

x=56

x=56

x+12 = 56+12 = 68

The largest angle is 68

the 4th choice is the correct one

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3