Find all missing parts for each triangle described. find angle measures to the nearest tenth of a degree and side lengths to the nearest tenth. show your work. place your final answers on the lines provided. if there are two solutions, place one solution on one set of lines and the other solution on the other set. 1: a=8m b=7.3m c=12.4m a= a= b= b= c= c= 2. b=100 degrees, a=15cm b=23cm c= c= a= a= c= c=

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

{3 + i, 3 - i, 3, -1}

step-by-step explanation: